LeetCode Digest
3 分鐘 閱讀文 (大約 375 個字)

438. Find All Anagrams in a String

題目
思路：怎麼判斷兩個字串是不是 anagram?

  • 可以把兩個字串都做排序，再看看是否相等，但這樣每次都要多花 O(n) 時間
  • 可以計算每個字母出現的頻率，再看看兩個字串的計算結果是否相等。雖然單獨算也是要 O(n)，但假如搭配 sliding window 移動的時候一個個字母加入計算，就不會有額外的時間複雜度
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標籤雲

android array authentication binary search binary search tree binary tree bit manipulation breadth-first search database depth-first search distributed system django docker dokku dynamic programming graph greedy hash table heap heroku java jwt linked list matrix mysql paas package management pipenv postgresql python recursion shortest path simulation sliding window sorting stack string tree two pointers

最新文章

彙整

標籤

android 2
array 5
authentication 1
binary search 1
binary search tree 1
binary tree 6
bit manipulation 2
breadth-first search 5
database 2
depth-first search 9
distributed system 1
django 1
docker 3
dokku 1
dynamic programming 4
graph 2
greedy 1
hash table 6
heap 1
heroku 1
java 1
jwt 1
linked list 5
matrix 1
mysql 1
paas 1
package management 1
pipenv 1
postgresql 1
python 9
recursion 11
shortest path 1
simulation 1
sliding window 1
sorting 1
stack 2
string 4
tree 7
two pointers 3

最新文章

彙整

標籤

android 2
array 5
authentication 1
binary search 1
binary search tree 1
binary tree 6
bit manipulation 2
breadth-first search 5
database 2
depth-first search 9
distributed system 1
django 1
docker 3
dokku 1
dynamic programming 4
graph 2
greedy 1
hash table 6
heap 1
heroku 1
java 1
jwt 1
linked list 5
matrix 1
mysql 1
paas 1
package management 1
pipenv 1
postgresql 1
python 9
recursion 11
shortest path 1
simulation 1
sliding window 1
sorting 1
stack 2
string 4
tree 7
two pointers 3
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