LeetCode Digest
4 分鐘 閱讀文 (大約 616 個字)

844. Backspace String Compare

題目
這邊記錄自己答案的演變和檢討，有需要的也可以直接跳到最後的 O(1) space complexity 解答

一開始的思路：用遞增的 index 同時 go through 這兩個字串，按照裡面的 backspace hint build 出兩個新的字串再來看看是否相等

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LeetCode Digest
9 分鐘 閱讀文 (大約 1291 個字)

142. Linked List Cycle II

題目
思路：最直覺的作法就是從頭開始沿著 next 一直走，然後用一個 set 來存放走過的 node，如果再次走到已走過的 node 就是 cycle 起點

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LeetCode Digest
2 分鐘 閱讀文 (大約 282 個字)

3Sum

題目
思路：

  • 用三個指標，iterate 最左邊那個，找出對應於每個 left 指標的所有 result
  • 先把 nums 排序，如此移動 mid, right 指標時就有個依據

Python3 solution

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分類

標籤雲

android array authentication binary search binary search tree binary tree bit manipulation breadth-first search database depth-first search distributed system django docker dokku dynamic programming graph greedy hash table heap heroku java jwt linked list matrix mysql paas package management pipenv postgresql python recursion shortest path simulation sliding window sorting stack string tree two pointers

最新文章

彙整

標籤

android 2
array 5
authentication 1
binary search 1
binary search tree 1
binary tree 6
bit manipulation 2
breadth-first search 5
database 2
depth-first search 9
distributed system 1
django 1
docker 3
dokku 1
dynamic programming 4
graph 2
greedy 1
hash table 6
heap 1
heroku 1
java 1
jwt 1
linked list 5
matrix 1
mysql 1
paas 1
package management 1
pipenv 1
postgresql 1
python 9
recursion 11
shortest path 1
simulation 1
sliding window 1
sorting 1
stack 2
string 4
tree 7
two pointers 3

最新文章

彙整

標籤

android 2
array 5
authentication 1
binary search 1
binary search tree 1
binary tree 6
bit manipulation 2
breadth-first search 5
database 2
depth-first search 9
distributed system 1
django 1
docker 3
dokku 1
dynamic programming 4
graph 2
greedy 1
hash table 6
heap 1
heroku 1
java 1
jwt 1
linked list 5
matrix 1
mysql 1
paas 1
package management 1
pipenv 1
postgresql 1
python 9
recursion 11
shortest path 1
simulation 1
sliding window 1
sorting 1
stack 2
string 4
tree 7
two pointers 3
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